Reply To: Integrali indefiniti di funzioni trigonometriche [esercizi]

  • Gianmarco

    Member
    20 Maggio 2023 at 18:46

    ok quindi diventa

    \(\displaystyle{\int}\dfrac{\sin x\left(\dfrac{1-2\cos^2x+1}{2}\right)}{\cos^3x}dx\)

    semplificando…

    \(\displaystyle{\int}\dfrac{\sin x\left(1-\cos^2x\right)}{\cos^3x}dx\)

    poi divido l’integrale in due?

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